# HDU 2092 整数解 --- 水题

x+y = n, x*y = m;

y = n - x;

x * ( n - x) = m

nx - x^2 = m;

x^2 - nx + m = 0;

△ = sqrt(n^2 - 4m)

```/* HDU 2092 整数解 --- 水题 */
#include <cstdio>
#include <cmath>

int main()
{
double n, m;
while (scanf("%lf%lf", &n, &m) == 2 && (n+m)){
n = n*n - 4 * m;
m = (int)sqrt(n);
if (m*m == n){
printf("Yes\n");
}
else{
printf("No\n");
}
}

return 0;
}```

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