# lintcode 中等题：kth-largest-element 第k大元素

#### 第k大元素

```class Solution {
/*
* @param k : description of k
* @param nums : array of nums
* @return: description of return
*/
public int kthLargestElement(int k, int[] nums) {
return quickSort(nums,0,nums.length-1,k);

}
public int quickSort(int[] nums,int left,int right,int k){
int i = left;
int j = right;
int tmp = nums[i];
while(i<j){
while(i<j && tmp>=nums[j]) j--;
if(i<j){
nums[i]=nums[j];
i++;
}
while(i<j && tmp<nums[i]) i++;
if(i<j){
nums[j]=nums[i];
j--;
}

}
if(i == k -1){
return tmp;
}else if(i< k-1){
return quickSort(nums,i+1,right,k);
}else{
return quickSort(nums,left,i-1,k);
}
}
};```

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